#KhanhHuyen2006 - Xin câu trả lời hay nhất
`x^2 - \sqrt{3} x - 2 - \sqrt{6} = 0`
`-> Δ = 3 + 4 (2 + \sqrt{6}) = 3 + 8 + 4 . \sqrt{6} = 11 + 2 . 2 . \sqrt{2} . \sqrt{3} = 8 + 2 \sqrt{2} . \sqrt{3} + 3 = (2 \sqrt{2} + \sqrt{3})^2 -> \sqrt{Δ} = 2 \sqrt{2} + \sqrt{3}`
`->` Ta sẽ có HPT
`->` \(\left[ \begin{array}{l}(\sqrt{3} + 2 \sqrt{2}+ \sqrt{3}) : 2\\(\sqrt{3}- 2\sqrt{2}-\sqrt{3}) : 2\end{array} \right.\)
`->` \(\left[ \begin{array}{l}x =\sqrt{2} + \sqrt{3}\\x=- \sqrt{2}\end{array} \right.\)
