Đáp án:
Giải thích các bước giải:
$2\sqrt{\frac{16}{3}}-3\sqrt{\frac{1}{27}}-6\sqrt{\frac{4}{75}}.\sqrt{3}$
$=2\sqrt{\frac{16}{3}}-3\sqrt{\frac{1}{27}}-6\sqrt{\frac{12}{75}}$
$=\sqrt{\frac{16}{3}.2^2}-\sqrt{\frac{1}{27}.3^2}-\sqrt{\frac{12}{75}.6^2}$
$=\sqrt{\frac{64}{3} }-\sqrt{\frac{1}{3} }-\sqrt{\frac{144}{25}}$
$=\frac{8\sqrt{3}}{3}-\frac{\sqrt{3}}{3}-2,4$
$=\frac{7\sqrt{3}}{3}-2,4$
$=\frac{-36+35\sqrt{3}}{5}$
