$2\dfrac{1}{3}:\dfrac{3}{4}=\dfrac{1}{2}:(2x-3)$
$⇔\dfrac{7}{3}.\dfrac{4}{3}=\dfrac{1}{2}:(2x-3)$
$⇔\dfrac{28}{9}=\dfrac{1}{2}:(2x-3)$
$⇔2x-3=\dfrac{1}{2}:\dfrac{28}{9}$
$⇔2x-3=\dfrac{9}{56}$
$⇔2x=\dfrac{9}{56}+3$
$⇔2x=\dfrac{177}{56}$
$⇔x=\dfrac{177}{56} : 2$
$⇔x=\dfrac{177}{112}$
Vậy $x=\dfrac{177}{112}$