Đáp án:
Giải thích các bước giải:
10-|x+3|=-4-(-10)
10-|x+3|= -4+10
10-|x+3|= 6
|x+3| = 10-6
|x+3| =4
=> x+3=4
x=4-3
x=1
hay x+3=-4
x=-4 -3
x=-7
Chúc bạn học thiệt thiệt tốt nhé !
$10-|×+3|=-4-(-10)$
$10-|×+3|=6$
$|×+3|=4$
$⇒$ \(\left[ \begin{array}{1}x+3=4⇒x=-1\\x+3=-4⇒x=-7\end{array} \right.\)
$Vậy$ $x∈{-1;-7}$
2 câu trên bn viết thiếu đề
lần sau cẩn thận hơn nhé ^ω^
Giải phương trình bài này cho em vs
Cân bằng các phương trình hóa học sau: 1) Fe + O2 -------------- > Fe3O4 2) Al + O2 Al2O3 3) P + O2 P2O5 4) SO3 + H2O H2 SO4 5) P2O5 + H2O H3 PO4 6) KMnO4 K2MnO4 + MnO2 + O2 7) H2 SO4 + KOH K2 SO4 + H2O 8) SO2 + O2 SO3 9) H3 PO4 + NaOH Na3PO4 + H2O 10) CO2 + Ca(OH)2 CaCO3 + H2O
Tìm x: a) 56 + X × 9 = 146 b) X ÷27 +30 = 111
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Mn giúp e hai bài này gấp gấp gấp gấp với ạ. E cảm ơn lắm lắm ạ
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Cho biết tỉ số AB/CD=4/5 và CD=20cm. Tính độ dài AB?
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M = ($\frac{x√x + 1 }{x - 1 }$ : (√x + $\frac{√x}{√x - 1}$ Rút gọn M và tìm x để M < 0
giup mik: cho tam giác abc cân tại a. gọi d là trung điểm của ab và e là trung điểm ac. trên tia đôi tia ed vẽ điểm bf sao cho eb là trung điểm của df. chứng minh rằng: a) da=cf ; b) ad//cf ; c) tam giác bdc=fcd => df//bc ; đ)e//bc & de=1/2bc
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