+(x +2y)
Bài 14: Tìm x, biết
* (x - 5)(x + 5)-(x + 3)° + 3(x - 2)° = (x + 1)° - (x + 4)(x - 4) + 3x?
9 (2x + 3)° + (x - 1)(x + 1) = 5(x + 2)° – (x - 5)(x + 1) + (x + 4)°
3 (-x + 5) (x - 2) + (x - 7)(x + 7) = (3x + 1) - (3x – 2) (3x + 2)
(5x – 1)(x + 1) – 2(x- 3)° = (x+ 2)(3x – 1) – (x + 4)° +(x² - x)
5) (4x – 1)° – (3x + 2)(3x – 2) = (7x - 1)(x + 2) + (2x + 1) - (4x² +7) U
6) (2x + 3) – (5x – 4)(5x + 4) = (x +5) - (3x -1)(7x + 2) – (x²
3)
+1)レ
7) (1– 3x)-(x – 2) (9x + 1) = (3x - 4)(3x + 4) - 9(x + 3)
8) (3x + 4)(3x – 4) – (2x + 5) = (x – 5) + (2x + 1) – (x² - 2x) (x – 1ý
9) (x – 7)(x + 1) - (x- 3) = (3x - 5)(3x + 5) - (3x + 1)° + (x-2)° - x² V
10) –5(x + 3)° + (x - 1)(x÷1) + (2x – 3) = (5x – 2)° - 5x (5x + 3)
11) (x – 1)° + 3(x - 3) - (x + 2)(x - 2x + 4) = (x + 2) – (x - 3)(x² + 9)'
- 6x² + 5
12) (x – 5)(x + 5) – (x – 2)° – 7x + (x + 1)(x - x + 1) = (x + 3)° – (x° + 9x³)
13) (x – 4)° – (x – 5)(x² + 5x + 25) = (x + 2)(x² – 2:: + 4) -- (x + 4) - (x- 7) V
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4) (x + 1)° – (x + 3)(x² -3x +9) = (x - 3)° + 3(2x +1)-(x- 5x +1)
3(2x+1) -(x - 5x +1)
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Sinh Học lớp 12
