|x-3| - 16 = - 4
|x-3| = ( - 4 ) + 16
|x-3| = 12
\(\Rightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=12+3\\x=\left(-12\right)+3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
Vậy x \(\in\) { 15;-9 }
