$(x - 3)(2x - 1)=(2x - 1)(2x+3)$
$⇔(x-3)(2x-1)-(2x-1)(2x+3)=0$
$⇔(2x-1)(x-3-2x-3)=0$
$⇔(2x-1)(-x-6)=0$
$⇔$ \(\left[ \begin{array}{l}2x-1=0\\-x-6=0\end{array} \right.\)
$⇔$ \(\left[ \begin{array}{l}2x=1\\-x=6\end{array} \right.\)
$⇔$ \(\left[ \begin{array}{l}x=1/2\\x=-6\end{array} \right.\)
