$n_{O_{2}}$=3,2 (mol)
⇒$V_{O_{2}(đktc)}$= n.22,4 =0,32.22,4=7,168(l)
⇒$V_{O_{2}(đkt)}$= n.24 =0,32.24=7,68(l)
$n_{CO_{2}}$=1,45 (mol)
⇒$V_{CO_{2}(đktc)}$=n.22,4=1,45.22,4=32,48(l)
⇒$V_{CO_{2}(đkt)}$=n.24=1,45.24=34,8(l)
$n_{NO_{2}}$=0,2 (mol)
⇒$V_{NO_{2}(đktc)}$=n.22,4=0,2.22,4=4,48(l)
⇒$V_{CO_{2}(đkt)}$=n.24=0,2.24=4,8(l)
$n_{SO_{2}}$=0,02 (mol)
⇒$V_{SO_{2}(đktc)}$=n.22,4=0,02.22,4=0,448(l)
⇒$V_{SO_{2}(đkt)}$=n.24=0,02.24=0,48(l)
$n_{N_{2}}$=0,03 (mol)
⇒$V_{N_{2}(đktc)}$=n.22,4=0,03.22,4=0,672(l)
⇒$V_{N_{2}(đkt)}$=n.24=0,03.24=0,72(l)
$n_{N_{2}O}$=0,04 (mol)
⇒$V_{N_{2}O(đktc)}$=n.22,4=0,04.22,4=0,896(l)
⇒$V_{N_{2}O(đkt)}$=n.24=0,04.24=0,96(l)
$n_{NH_{3}}$=0,015 (mol)
⇒$V_{NH_{3}O(đktc)}$=n.22,4=0,015.22,4=0,336(l)
⇒$V_{NH_{3}O(đkt)}$=n.24=0,015.24=0,36(l)
$n_{H_{2}}$=0,06 (mol)
⇒$V_{N_{2}(đktc)}$=n.22,4=0,06.22,4=1,334(l)
⇒$V_{O_{2}(đkt)}$= n.24 =0,06.24=1,44(l)
$n_{H_{2}S}$=0,08 (mol)
⇒$V_{H_{2}S(đktc)}$=n.22,4=0,08.22,4=1,792(l)
⇒$V_{H_{2}S(đkt)}$=n.24=0,08.24=1,92(l)
cuthilien
