Giải thích các bước giải:
`3= (2a+4b-2 )/ (2a+6-2)`
`⇔3=(2(a+2b-1))/(2(a+3-1))=(a+2b-1)/(a+3-1)=(a+2b+2-3)/(a+2)=1+(2b-3)/(a+2)`
`⇔(2b-3)/(a+2)=2`
`⇔2b-3=2.(a+2)`
`⇔2b-3=2a+4`
`⇔2a-2b=-7`
`⇔2(a-b)=-7`
`⇔a-b=-7/2`
`⇔a=b-7/2; b=a+7/2∀a,b∈Q`
Đáp án:
a = b - 7/2
3= (2a+4b-2)/(2a+6-2 )=> 3 = (2a + 4b - 2)/(2a + 4)=> 3 = (a+2b-1)/(a+2)=< a + 2b - 1 = 3(a + 2)=> 3a+6=a+2b-1=< 2a=2b-7=> a = b - 7/2
Đề bài: Khai triển biểu thức a) (2x+y)^2 b) (2-xy)^2 c) (3x-2y) (3x+2y) d) 2 (x^2 +1/2y) (2x^2 -y)
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