Đáp án:
`(x^3-3x^2+2x-6):(x-3)=x^2+2`
Giải thích các bước giải:
Cách `1:`
$\begin{array}{c|c}\qquad \quad \quad x^3-3x^2+2x-6&x-3\\\hline x^3-3x^2&x^2+2\\\text{______________________}\\2x-6\\2x-6\\\text{______________________}\\0\end{array}$
Vậy `(x^3-3x^2+2x-6):(x-3)=x^2+2`
Cách `2:`
`(x^3-3x^2+2x-6):(x-3)`
`=(x^3-3x^2+2x-6)/(x-3)`
`=(x^2.(x-3)+2.(x-3))/(x-3)`
`=((x^2+2)(x-3))/(x-3)`
`=x^2+2`
Vậy `(x^3-3x^2+2x-6):(x-3)=x^2+2`
