Đáp án+Giải thích các bước giải:
$\text{ /$\dfrac{3}{4}$-x/+$\dfrac{1}{6}$=1$\dfrac{1}{6}$}$
$\text{ ⇒ /$\dfrac{3}{4}$-x/+$\dfrac{1}{6}$=1$\dfrac{7}{6}$}$
$\text{⇒ /$\dfrac{3}{4}$-x/ = 1 }$
TH1: $\text{$\dfrac{3}{4}$-x=-1}$
$\text{⇒ x = $\dfrac{3}{4}$-(-1) }$
$\text{⇒ x =$\dfrac{7}{4}$ }$
TH2: $\text{$\dfrac{3}{4}$-x=1}$
$\text{⇒ x = $\dfrac{3}{4}$-1 }$
$\text{⇒ x = -$\dfrac{1}{4}$ }$
Vậy `x∈{`$\dfrac{7}{4}$; -$\dfrac{1}{4}$}
