`3sqrt(x^2 - 4) - 5 = 4`
`⇒ 3sqrt(x^2 - 2^2) - 5 = 4`
`⇒ 3sqrt((x+2)(x-2)) - 5 = 4`
`⇒ 3sqrt((x+2)(x-2)) = 4 + 5`
`⇒ 3sqrt((x+2)(x-2)) = 9`
`⇒ 9(x+2)(x−2)=81`
`⇒ 9x^2−36=81`
`⇒ 9x^2=81+36`
`⇒ 9x^2=117`
`⇒ x^2 = 117/9`
`⇒ x^2 = 13`
`→ x = ±sqrt(13)`
Vậy `x = ±sqrt(13)`
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@Drew McIntyre