(3 + √5)(√10-√2)$\sqrt[]{3- √5 }$
= ( 3 + √5 )( √5 - 1)√2$\sqrt[]{3 -√5 }$
= ( 3 + √5 )(√5 - 1) $\sqrt[]{6- 2√5 }$
= ( 3 + √5)(√5 - 1) $\sqrt[]{( √5-1)² }$
= ( 3 + √5)(√5 -1)(√5 - 1)
=(3 + √5)(5 - √5 -√5 + )
= (3 +√5)(6- 2√5)
=18 - 6√5 + 6√5 -10
= 8
$\sqrt[]{5-2 \sqrt{7-2√6 }}$
= $\sqrt[]{5-2\sqrt{(√6-1)² }}$
= $\sqrt[]{5 -2√6 +2 }$
= $\sqrt[]{7 -2√6 }$
= $\sqrt[]{ (√6-1)² }$
= √6 - 1
😊