a) x.($\frac{3}{5}$)³=$\frac{3}{5}$
⇒ x.($\frac{3}{5}$) ³-$\frac{3}{5}$=0
$\frac{3}{5}$.((x.$\frac{3}{5}$)²-1)=0
=> x.($\frac{3}{5}$)² -1=0
x.($\frac{3}{5}$)² =1
x= ($\frac{5}{3}$)²
b) 2(3x+7)-5(x-4)=0
6x+14-5x+20=0
x+34=0
x= -34
c) x - $\frac{7}{6}$ = $\frac{2³}{16}$
x - $\frac{7}{6}$= $\frac{1}{2}$
x= $\frac{1}{2}$ + $\frac{7}{6}$
x= $\frac{5}{3}$
