Đáp án đúng: D
Giải chi tiết:Ta có: \(\left. \begin{array}{l}3x + 5\,\, \vdots \,\,x - 2\\x - 2\,\, \vdots \,\,x - 2\end{array} \right\} \Rightarrow \left. \begin{array}{l}3x + 5\,\, \vdots \,\,x - 2\\3\left( {x - 2} \right)\,\, \vdots \,\,x - 2\end{array} \right\} \Rightarrow \left. \begin{array}{l}3x + 5\,\, \vdots \,\,x - 2\\3x - 6\,\, \vdots \,\,x - 2\end{array} \right\} \Rightarrow \left( {3x + 5} \right) - \left( {3x - 6} \right)\,\, \vdots \,\,x - 2\)
\( \Rightarrow 3x + 5 - 3x + 6\,\, \vdots \,\,x - 2 \Rightarrow 11\,\, \vdots \,\,x - 2\)
\( \Rightarrow \left( {x - 2} \right) \in U\left( {11} \right) \Rightarrow x - 2 \in \left\{ { - 11;\,\, - 1;\,\,1;\,\,11} \right\}\)
\( \Rightarrow x \in \left\{ { - 9;\,\,1;\,\,3;\,\,13} \right\}\)
Vậy \(x \in \left\{ { - 9;\,\,1;\,\,3;\,\,13} \right\}\).
Chọn D.