Đáp án:
Giải thích các bước giải:
$\dfrac{-3}{7}.\dfrac{-1}{12}+\dfrac{-3}{7}.\dfrac{11}{6}-\dfrac{8}{3}$
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$=\dfrac{-3}{7}.(\dfrac{-1}{12}+\dfrac{22}{12})-\dfrac{8}{3}$
$ $
$=\dfrac{-3}{7}.\dfrac{7}{4}-\dfrac{8}{3}$
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$=\dfrac{-3}{4}-\dfrac{8}{3}$
$ $
$=\dfrac{-9}{12}-\dfrac{32}{12}$
$ $
$=\dfrac{-41}{12}$