(x - $\frac{3}{4}$)² = $\frac{5}{16}$ + $\frac{1}{4}$
(x - $\frac{3}{4}$)² = $\frac{5}{16}$ + $\frac{4}{16}$
(x - $\frac{3}{4}$)² = $\frac{9}{16}$
(x - $\frac{3}{4}$)² = $(\frac{3}{4})^{2}$
x - $\frac{3}{4}$ = $\frac{3}{4}$ hoặc x - $\frac{3}{4}$ = - $\frac{3}{4}$
x = $\frac{3}{4}$ + $\frac{3}{4}$ hoặc x = - $\frac{3}{4}$ + $\frac{3}{4}$
x = $\frac{6}{4}$ hoặc x = 0
x = $\frac{3}{2}$ hoặc x = 0
Vậy x = $\frac{3}{2}$ hoặc x = 0
