Đáp án:
Giải thích các bước giải:
\[\begin{array}{l}\sqrt 3 .\tan \,2x - 3 = 0\,\,\,\left( {DK:\,\,\,\,co\,s2x \ne 0 \Leftrightarrow x \ne \frac{\pi }{4} + \frac{{k\pi }}{2}} \right)\\ \Leftrightarrow \tan \,2x = \frac{3}{{\sqrt 3 }} = \sqrt 3 \\ \Leftrightarrow \tan \,\,2x = \tan \,\,\frac{\pi }{3}\\ \Leftrightarrow 2x = \frac{\pi }{3} + k\pi ,\,\,k \in Z\\ \Leftrightarrow x = \frac{\pi }{6} + \frac{{k\pi }}{2},\,\,k \in Z\,\,\,\left( {TM} \right)\end{array}\]
