Giải:
a) \(-\dfrac{36}{35}:\dfrac{9}{14}.\left(-\dfrac{1}{2}\right)^3\)
\(=-\dfrac{36}{35}.\dfrac{14}{9}.\left(-\dfrac{1}{8}\right)\)
\(=-\dfrac{36.14.\left(-1\right)}{35.9.8}\)
\(=-\dfrac{9.4.2.7.\left(-1\right)}{5.7.9.2.4}\)
\(=-\dfrac{-1}{5}\)
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b) \(\left[6+\left(\dfrac{1}{2}\right)^3-\dfrac{1}{2}\right]:\dfrac{3}{12}\)
\(=\left[6+\dfrac{1}{8}-\dfrac{1}{2}\right].\dfrac{12}{3}\)
\(=\left[\dfrac{48}{8}+\dfrac{1}{8}-\dfrac{4}{8}\right].4\)
\(=\dfrac{48+1-4}{8}.4\)
\(=\dfrac{45}{8}.4\)
\(=\dfrac{45}{2}\)
Vậy ...
