Đáp án:
Giải thích các bước giải:
`3sin^2 x+2sin\ x-1=0`
`⇔ (3sin\ x-1)(sin\ x+1)=0`
`⇔` \(\left[ \begin{array}{l}3\sin\ x-1=0\\\sin\ x+1=0\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}\sin\ x=\dfrac{1}{3}\\\sin\ x=-1\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=\arcsin\ (\dfrac{1}{3})+k2\pi\ (k \in \mathbb{Z})\\x=\pi-\arcsin\ (\dfrac{1}{3})+k2\pi\ (k \in \mathbb{Z})\\x=-\dfrac{\pi}{2}+k2\pi\ (k \in \mathbb{Z})\end{array} \right.\)
