\(\left(4x+\dfrac{2}{3}\right)\left(2x-\dfrac{1}{2}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}4x+\dfrac{2}{3}=0\\2x-\dfrac{1}{2}=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-1}{6}\\x=\dfrac{1}{4}\end{matrix}\right.\)
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