Ta có: \(\left(4x-3\right)^4=\left(4x-3\right)^2\)
\(\Leftrightarrow\left(4x-3\right)^2\left[\left(4x-3\right)^2-1\right]=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(4x-3\right)^2=0\\\left(4x-3\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x-3=\pm0\\4x-3=\pm1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}4x=3\\4x=4\\4x=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=1\\x=\dfrac{1}{2}\end{matrix}\right.\)
Vậy \(x=\dfrac{3}{4}\) hoặc \(x=1\) hoặc \(x=\dfrac{1}{2}\)
