m bình 1 tăng là mH2O
=> nH= 2nH2O= 2. 5,4/18= 0,6 mol => mH= 0,6g
Bình 2: CO2 tạo 2 muối
nCaCO3= 15/100= 0,15 mol
nCa(HCO3)2= 4,05/162= 0,025 mol
CO2+ Ca(OH)2 -> CaCO3+ H2O
2CO2+ Ca(OH)2 -> Ca(HCO3)2
=> nCO2= 0,15+ 0,025.2= 0,2 mol= nC
=> mC= 2,4g
%C= 2,4.100:4,6= 52,17%
%H= 0,6.100:4,6= 13%
%O= 100-52,17- 13= 34,83%