4) Ta có: $\overrightarrow{AB} = \left ( 3; 5 \right )$
$\to \Delta$ có $VTPT: \overrightarrow{n} = \left ( -5; 3 \right )$
$\to PTTQ: -5\left ( x - 1 \right ) + 3\left ( y + 3 \right ) = 0$
$\to 5x - 3y - 14 = 0$
5) Gọi trung điểm của $AB$ là $D$
$\to D\left ( \dfrac{5}{2}; -\dfrac{1}{2} \right )$
$\to \overrightarrow{CD} = \left ( \dfrac{9}{2}; \dfrac{1}{2} \right )$
$\to \Delta_{CD}$ có $VTPT: \overrightarrow{n_{CD}} = \left ( -\dfrac{1}{2}; \dfrac{9}{2} \right )$
$\to PTTQ: -\dfrac{1}{2}\left ( x + 2 \right ) + \dfrac{9}{2}\left ( y + 2 \right ) = 0$
$\to \dfrac{1}{2}x - \dfrac{9}{2}y - 8 = 0$
$\to x - 9y - 16 = 0$