`49/16 (5-2x)^2 - 25= 0`
`⇔[7/4 (5 - 2x)]^2 = 25`
`⇔(35/4 - 7/2 x)^2 = (±5)^2`
`⇒35/4 - 7/2 x = ±5`
`⇔` \(\left[ \begin{array}{l}\dfrac{35}{4}-\dfrac{7}{2}x=5\\\dfrac{35}{4}-\dfrac{7}{2}x=-5\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}\dfrac{7}{2}x=\dfrac{15}{4}\\\dfrac{7}{2}x=\dfrac{55}{4}\end{array} \right.\)
`⇔\(\left[ \begin{array}{l}x=\dfrac{15}{14}\\x=\dfrac{55}{14}\end{array} \right.\)
