$(5x-1)\bigg(2x-\dfrac{1}{3}\bigg)=0$
$⇔$\(\left[ \begin{array}{l}5x-1=0\\2x-\dfrac{1}{3}=0\end{array} \right.\)
$⇔$\(\left[ \begin{array}{l}5x=1\\2x=\dfrac{1}{3}\end{array} \right.\)
$⇔$\(\left[ \begin{array}{l}x=\dfrac{1}{5}\\x=\dfrac{1}{6}\end{array} \right.\)