$5x(x-2000)-x+2000=0$
$⇒5x(x-2000)-(x-2000)=0$
$⇒(5x-1)(x-2000)=0$
$⇒$\(\left[ \begin{array}{l}5x-1=0\\x-2000=0\end{array} \right.\)
$⇒$\(\left[ \begin{array}{l}5x=1\\x=2000\end{array} \right.\)
$⇒$\(\left[ \begin{array}{l}x=\frac{1}{5}\\x=2000\end{array} \right.\)
$vậy$ $x =$ {$\frac{1}{5} ; 2000$}
