Đáp án:
$a) ⇔x=\dfrac{-23}{48}$
$b) ⇔x=\dfrac{5}{12}$
Giải thích các bước giải:
$a) x+\dfrac{5}{4}+(x-\dfrac{1}{8})=\dfrac{1}{6}$
$⇔2x+\dfrac{5}{4}=\dfrac{1}{6}+\dfrac{1}{8}$
$⇔2x+\dfrac{5}{4}=\dfrac{7}{24}$
$⇔2x=\dfrac{-23}{24}$
$⇔x=\dfrac{-23}{48}$
$b) x+\dfrac{5}{4}=(\dfrac{4}{3}+\dfrac{1}{3})$
$⇔x+\dfrac{5}{4}=\dfrac{5}{3}$
$⇔x=\dfrac{5}{3}-\dfrac{5}{4}$
$⇔x=\dfrac{5}{12}$
