Đáp án:
$\text{7.}$
Giải thích các bước giải:
$\text{($6^{2020}$ + $6^{2019}$) ÷ $6^{2019}$.}$
$\text{= $\dfrac{6^{2020} + 6^{2019}}{6^{2019}}$.}$
$\text{= $\dfrac{6.6^{2019} + 1.6^{2019}}{6^{2019}}$.}$
$\text{= $\dfrac{(6 +1).6^{2019}}{6^{2019}}$.}$
$\text{= $\dfrac{6^{2019}.7}{6^{2019}}$.}$
$\text{= $\dfrac{1.7}{1}$.}$
$\text{= 7.}$