8. Lập phương trình chuyển động và phương trình vận tốc của các vật sau: a) Vật c/đ NDĐ: vị trí xuất phát nằm phần dương trục Ox cách gốc tọa độ 50m chuyển động theo chiều dương với vận tốc đầu 30m/s và có gia tốc 4m/s2

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8. Lập phương trình chuyển động và phương trình vận tốc của các vật sau: a) Vật c/đ NDĐ: vị trí xuất phát nằm phần dương trục Ox cách gốc tọa độ 50m chuyển động theo chiều dương với vận tốc đầu 30m/s và có gia tốc 4m/s2 b) Vật c/đ NDĐ: vị trí xuất phát nằm phần dương trục Ox cách gốc tọa độ 50m chuyển động về gốc tọa độ với vận tốc đầu 10m/s và có gia tốc 5m/s2 c) Vật c/đ CDĐ: vị trí xuất phát nằm phần âm trục Ox cách gốc tọa độ 150m chuyển động theo chiều dương với vận tốc đầu 20m/s và có gia tốc 4m/s2 d) Vật c/đ CDĐ: vị trí xuất phát nằm phần dương trục Ox cách gốc tọa độ 50m chuyển động về gốc tọa độ với vận tốc đầu 30m/s và có gia tốc 4m/s2 e) Vật xuất phát tại gốc tọa độ đi ngược chiều dương, c/đ CDĐ, với vận tốc đầu 24m/s và với gia tốc 10m/s2 f) Vị trí xuất phát cách gốc tọa độ 120m, vật chuyển động nhanh dần không vận tốc đầu, biết sau khi đi được 5 giây vật đạt vận tốc 20 m/s GIÚP TỚ VỚI AHUHUUU

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minhchinhqd2002

a) Phương trình chuyển động là:

`x=x_0+v_0t+\frac{1}{2}at^2=50+30t+2t^2 \ (m)`

Phương trình vận tốc là:

$v=v_0+at=30+4t \ (m/s)$

b) Phương trình chuyển động là:

`x=x_0+v_0t+\frac{1}{2}at^2=50-10t+2,5t^2 \ (m)`

Phương trình vận tốc là:

$v=v_0+at=-10+5t \ (m/s)$

c) Phương trình chuyển động là:

`x=x_0+v_0t+\frac{1}{2}at^2=-150+20t-2t^2 \ (m)`

Phương trình vận tốc là:

$v=v_0+at=20-4t \ (m/s)$

d) Phương trình chuyển động là:

`x=x_0+v_0t+\frac{1}{2}at^2=50-30t+2t^2 \ (m)`

Phương trình vận tốc là:

$v=v_0+at=-30+4t \ (m/s)$

e) Phương trình chuyển động là:

`x=x_0+v_0t+\frac{1}{2}at^2=-24t+5t^2 \ (m)`

Phương trình vận tốc là:

$v=v_0+at=-24+10t \ (m/s)$

f) Gia tốc của vật là:

$a=\dfrac{v-v_0}{t}=\dfrac{20-0}{5}=4 \ (m/s^2)$

Phương trình chuyển động là:

`x=x_0+v_0t+\frac{1}{2}at^2=120+2t^2 \ (m)`

Hoặc `x=-120+2t^2 \ (m)`

Phương trình vận tốc là:

$v=v_0+at=4t \ (m/s)$

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