\(A = \left[ {0;2} \right] \cup \left( {4;6} \right),\)\(B = \left( { - 5;0} \right] \cup \left( {3;5} \right)\)
A.\(\begin{array}{l}A \cup B = \left( { - 5;2} \right] \cup \left( {3;6} \right)\\A \cap B = \left\{ 0 \right\} \cup \left( {4;5} \right)\\A\backslash B = \left( {0;2} \right] \cup \left[ {5;6} \right)\\B\backslash A = \left( { - 5;0} \right) \cup \left( {3;6} \right]\end{array}\)
B.\(\begin{array}{l}A \cup B = \left( { - 5;2} \right] \cup \left( {3;6} \right)\\A \cap B = \left\{ 0 \right\} \cup \left( {3;5} \right)\\A\backslash B = \left( {0;2} \right] \cup \left[ {5;6} \right)\\B\backslash A = \left( { - 5;0} \right) \cup \left( {3;4} \right]\end{array}\)
C.\(\begin{array}{l}A \cup B = \left( { - 5;2} \right] \cup \left( {3;6} \right)\\A \cap B = \left\{ 0 \right\} \cup \left( {4;5} \right)\\A\backslash B = \left( {0;2} \right] \cup \left[ {5;6} \right)\\B\backslash A = \left( { - 5;0} \right) \cup \left( {3;4} \right]\end{array}\)
D.\(\begin{array}{l}A \cup B = \left( { - 5;0} \right] \cup \left( {3;6} \right)\\A \cap B = \left\{ 0 \right\} \cup \left( {4;5} \right)\\A\backslash B = \left( {0;2} \right] \cup \left[ {5;6} \right)\\B\backslash A = \left( { - 5;0} \right) \cup \left( {3;4} \right]\end{array}\)
A.\(\begin{array}{l}A \cup B = \left( { - 5;2} \right] \cup \left( {3;6} \right)\\A \cap B = \left\{ 0 \right\} \cup \left( {4;5} \right)\\A\backslash B = \left( {0;2} \right] \cup \left[ {5;6} \right)\\B\backslash A = \left( { - 5;0} \right) \cup \left( {3;6} \right]\end{array}\)
B.\(\begin{array}{l}A \cup B = \left( { - 5;2} \right] \cup \left( {3;6} \right)\\A \cap B = \left\{ 0 \right\} \cup \left( {3;5} \right)\\A\backslash B = \left( {0;2} \right] \cup \left[ {5;6} \right)\\B\backslash A = \left( { - 5;0} \right) \cup \left( {3;4} \right]\end{array}\)
C.\(\begin{array}{l}A \cup B = \left( { - 5;2} \right] \cup \left( {3;6} \right)\\A \cap B = \left\{ 0 \right\} \cup \left( {4;5} \right)\\A\backslash B = \left( {0;2} \right] \cup \left[ {5;6} \right)\\B\backslash A = \left( { - 5;0} \right) \cup \left( {3;4} \right]\end{array}\)
D.\(\begin{array}{l}A \cup B = \left( { - 5;0} \right] \cup \left( {3;6} \right)\\A \cap B = \left\{ 0 \right\} \cup \left( {4;5} \right)\\A\backslash B = \left( {0;2} \right] \cup \left[ {5;6} \right)\\B\backslash A = \left( { - 5;0} \right) \cup \left( {3;4} \right]\end{array}\)
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Hóa Học lớp 12
