`a)`
`x - 17/36 = (-15)/16 . 4/27`
`⇒ x - 17/36 = -5/36`
`⇒ x = -5/36 + 17/36 = 12/36 = 1/3`
`b)`
`4/15 - x = -16/25 . 5/64`
`⇒ 4/15 - x = -1/20`
`c)`
`|x - 2| = -9/12 . (-4)/3`
`⇒ |x - 2| = 1`
`⇒ x - 2 = 1 ; x - 2 = -1`
`⇒ x = 3 ; x = 1`
`d)`
`text(Ko rõ)`