Đáp án + Giải thích các bước giải:
`a//(2x+1)(x+2)=0`
`⇒` \(\left[ \begin{array}{l}2x+1=0\\x+2=0\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}2x=-1\\x=-2\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}x=-\frac{1}{2}\\x=-2\end{array} \right.\)
Vậy `x∈{-(1)/(2);-2}`
`b//17x+3(-16x-37)=2x-43`
`⇒17x-48x-111=2x-43`
`⇒17x-48x-2x=111-43`
`⇒-33x=68`
`=>x=-(68)/(33)`
`c//-2(x+3)-15=3(4+2x)+7`
`=>-2x-6-15=12+6x+7`
`=>-2x-6x=6+15+12+7`
`=>-8x=40`
`=>x=-5`
