Đáp án:
b) x=1
Giải thích các bước giải:
\(\begin{array}{l}
a)DK:x \ne \dfrac{1}{2}\\
\dfrac{{2x - 1}}{{ - 2}} = \dfrac{{50}}{{1 - 2x}}\\
\to \dfrac{{2x - 1}}{2} = \dfrac{{50}}{{2x - 1}}\\
\to {\left( {2x - 1} \right)^2} = 100\\
\to \left| {2x - 1} \right| = 10\\
\to \left[ \begin{array}{l}
2x - 1 = 10\\
2x - 1 = - 10
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{{11}}{2}\\
x = - \dfrac{9}{2}
\end{array} \right.\\
b){2^{2x + 1}} + {4^{x + 3}} = 264\\
\to {2.4^x} + {4^3}{.4^x} = 264\\
\to {66.4^x} = 264\\
\to {4^x} = 4\\
\to x = 1
\end{array}\)
