a)`x^2-3x+2=0`
`<=>(x-2)(x-1) = 0`
`<=>`\(\left[ \begin{array}{l}x-2=0\\x-1=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=2\\x=1\end{array} \right.\)
Vậy: `S={2;1}`
b)`(4x-10)(24+5x) = 0`
`<=>`\(\left[ \begin{array}{l}4x-10=0\\24+5x=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}4x=10\\5x=-24\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\frac{5}{2}\\x=-\frac{24}{5}\end{array} \right.\)
Vậy: `S={5/2;-24/5}`
Mong bn cho mk hay nhất nhé :V
