Đáp án:
a) `\frac{2}{3}- 4.(\frac{1}{2}+\frac{3}{4})`
`=\frac{2}{3}- 4. \frac{5}{4}`
`=\frac{2}{3}- 5`
`=-\frac{13}{3}`
b) `(-\frac{5}{9}) . \frac{3}{11} + (-\frac{13}{18}) . \frac{3}{11} `
`=[(-\frac{5}{9}) + (-\frac{13}{18})] . \frac{3}{11} `
`= (-\frac{23}{18}) . \frac{3}{11} `
`= -\frac{23}{66}`
c) `(-\frac{1}{3} + \frac{5}{6}) . 11 - 7`
`= \frac{1}{2} . 11 - 7`
`= \frac{11}{2} - 7`
`= -\frac{3}{2} `
d) `(-\frac{2}{3}) . \frac{3}{11} + (-\frac{16}{9}) . \frac{3}{11} `
`=[(-\frac{2}{3}) + (-\frac{16}{9})] . \frac{3}{11} `
`=(-\frac{22}{9}) . \frac{3}{11} `
`=-\frac{2}{3}`
e) `\frac{11}{125} - \frac{17}{18} - \frac{5}{7} + \frac{4}{9} + \frac{17}{14}`
`=\frac{11}{125} + [(\frac{-17}{18} + \frac{4}{9}) + (\frac{-5}{7} + \frac{17}{14})]`
`=\frac{11}{125} + [(\frac{-1}{2}) + \frac{1}{2} ]`
`=\frac{11}{125} + 0`
`=\frac{11}{125} `
