$\text {a, (2x-3)(6-2x) =0}$
$\text {⇔\(\left[ \begin{array}{l}2x-3 =0\\6-2x =0\end{array} \right.\) }$
$\text {⇔\(\left[ \begin{array}{l}2x=3\\2x=6\end{array} \right.\) }$
$\text {⇔\(\left[ \begin{array}{l}x=\frac{3}{2} \\x=3\end{array} \right.\) }$
$\text {Vậy x=$\frac{3}{2}$ hoặc x=3}$
$\text {b, (x+$\frac{1}{2}$)(2-3x) =0 }$
$\text {⇔\(\left[ \begin{array}{l}x+\frac{1}{2}= 0 \\2-3x =0\end{array} \right.\) }$
$\text {⇔\(\left[ \begin{array}{l}x=\frac{-1}{2} \\3x=2\end{array} \right.\) }$
$\text {⇔\(\left[ \begin{array}{l}x=\frac{-1}{2} \\x=\frac{2}{3} \end{array} \right.\) }$
$\text {Vậy x=$\frac{-1}{2}$ hoặc x=$\frac{2}{3}$ }$
$\text {c, 2x(x²+1)(x²-9) =0}$
$\text {⇔\(\left[ \begin{array}{l}2x =0\\x²+1 =0\\x²-9 =0\end{array} \right.\) }$
$\text {⇔\(\left[ \begin{array}{l}x =0\\x²+1 =0 (vô nghiệm)\\x²=9\end{array} \right.\) }$
$\text {⇔\(\left[ \begin{array}{l}x =0\\x=3\\x=-3\end{array} \right.\) }$
$\text {Vậy x=0 hoặc x=3 hoặc x=-3}$
$\text {Chúc bạn học tốt~}$
$\text {@lamtung2}$
