a. $(x-2)(5-x)=0 $
⇒ \(\left[ \begin{array}{l}x-2=0\\5-x=0\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=2\\x=5\end{array} \right.\)
Vậy S={$2;5$}
b. $(x+1)(x^2+1)=0$
⇒ \(\left[ \begin{array}{l}x+1=0\\x^2+1=0(vô lí)\end{array} \right.\)
⇒ $x+1=0$
⇒ $x=-1$
Vậy S={$-1$}