a) (x-3).(2y+1)=7
⇒(x-3); (2y+1) ∈Ư(7)={±1;±7}
Ta có bảng sau:
x 2 4 -4 10
x-3 -1 1 -7 7
2y+1 -7 7 -1 1
y -4 3 -1 0
Vậy (x;y)=(2;-4),(4;3),(-4;-1),(10,0)
b) (2x+1).(3y-2)=-55
⇒(2x+1); (3y-2) ∈Ư(-55)={±1;±5;±11;±55}
x -1 0 -3 2 -28 27
2x+1 -1 1 -5 5 -55 55
3y-2 55 -55 11 -11 1 -1
y 19 53/3 13/3 -3 1 1/3
Vì (x;y) ∈Z ⇒(x;y)=(-1;19),(2;-3),(-28;1).