Đáp án:
Giải thích các bước giải:
$a) (x-3).(2y+1)=7=7.1=1.7=(-1).(-7)=(-7).(-1)$
$Nếu (x-3).(2y+1)=7.1$
$⇒ x=10; y=0$
$Nếu (x-3).(2y+1)=1.7$
$⇒ x=4; y=3$
$Nếu (x-3).(2y+1)=(-1).(-7)$
$⇒ x=2; y=-4$
$Nếu (x-3).(2y+1)=(-7).(-1)$
$⇒ x=-4; y=-1$
Vậy...
$(2x+1).(3y-2)=-55=-55.1=1.(-55)=(-1).55=55.(-1)=5.(-11)=(-11).5=11.(-5)=(-5).11$
$Nếu (2x+1).(3y-2)=-55.1$
$⇒x=-28; y=1$
$Nếu (2x+1).(3y-2)=1.(-55)$
$⇒x=0; y=\frac{-53}{3}$
$Nếu (2x+1).(3y-2)=-1.55$
$⇒x=-1; y=19$
$Nếu (2x+1).(3y-2)= 55.(-1)$
$⇒ x=27; y=\frac{1}{3}$
$Nếu (2x+1).(3y-2)=5.(-11)$
$⇒ x=2; y=(-3)$
$Nếu (2x+1).(3y-2)=(-11).5$
$⇒x=(-6); y=\frac{7}{3}$
$Nếu (2x+1).(3y-2)=-5.11$
$⇒x=(-3); y=\frac{13}{3}$
$Nếu (2x+1).(3y-2)=11.(-5)$
$⇒ x=5; y=(-1)$
Vậy...
