Đáp án + Giải thích các bước giải:
`a)`
`4/3+2/3x=16/3`
`⇔2/3x=16/3-4/3`
`⇔2/3x=12/3`
`⇔2/3x=4`
`⇔x=6`
Vậy `S={6}`
`b)`
`(x+1/3).(3/4-2x)=0`
$⇔\left[\begin{matrix}x+\dfrac{1}{3}=0\\ \dfrac{3}{4}-2x=0\end{matrix}\right.$
$⇔\left[\begin{matrix}x=\dfrac{-1}{3}\\ x=\dfrac{3}{8}\end{matrix}\right.$
Vậy `S={-1/3;3/8}`
`c)`
`-4/5x+4/3x=-4/3`
`⇔-x(4/5-4/3)=-4/3`
`⇔-x(-8/15)=-4/3`
`⇔-x=5/2`
`⇔x=-5/2`
Vậy `S={-5/2}`
`#Study well`
