Đáp án:
a) `x in { -43/28 ; 71/28 }`
b) `x in { -1 ; 0 }`
Giải thích các bước giải:
a) `-5/7 - |1/2-x| = -11/4`
`to |1/2-x|=-5/7-(-11/4)`
`to |1/2-x|=57/28`
`to` \(\left[ \begin{array}{l}\dfrac{1}{2}-x=\dfrac{57}{28}\\\dfrac{1}{2}-x=-\dfrac{57}{28}\end{array} \right.\)`to` \(\left[ \begin{array}{l}x=-\dfrac{43}{28}\\x=\dfrac{71}{28}\end{array} \right.\)
Vậy `x in { -43/28 ; 71/28 }`
b) `text{Bổ sung đề :}` `x in ZZ`
`-4 1/3 . ( 1/2 - 1/6 ) <= x <= -2/3 . ( 1/3 - 1/2 - 3/4 )`
`to -13/3 . 1/3 <= x <= -2/3 . (-11/12)`
`to -13/9 <= x <= 11/18`
`to -1,4 <= x <= 0,6`
Mà `x in ZZ`
`to x in { -1 ; 0 }`
Vậy `x in { -1 ; 0 }`
