Giải thích các bước giải:
Ta có:
\(\begin{array}{l}
a,\\
\frac{{7x - 1}}{{6 + 2x}} = \frac{{16 - x}}{5}\,\,\,\,\,\left( {x \ne - 3} \right)\\
\Leftrightarrow \left( {7x - 1} \right).5 = \left( {16 - x} \right).\left( {6 + 2x} \right)\\
\Leftrightarrow 35x - 5 = 96 + 32x - 6x - 2{x^2}\\
\Leftrightarrow 2{x^2} + 9x - 101 = 0\\
\Leftrightarrow x = \frac{{ - 9 \pm \sqrt {889} }}{4}\\
b,\\
\frac{{{{\left( {x + 2} \right)}^2}}}{{2x - 3}} - 1 = \frac{{{x^2} + 10}}{{2x - 3}}\\
\Leftrightarrow \left[ {\frac{{{{\left( {x + 2} \right)}^2}}}{{2x - 3}} - \frac{{{x^2} + 10}}{{2x - 3}}} \right] = 1\\
\Leftrightarrow \frac{{{x^2} + 4x + 4 - {x^2} - 10}}{{2x - 3}} = 1\\
\Leftrightarrow \frac{{4x - 6}}{{2x - 3}} = 1\\
\Leftrightarrow 2 = 1\,\,\,\,\,\,\left( {vn} \right)
\end{array}\)
