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laosoaica5
2 năm trước
A = ( $\frac{1}{√x - 1}$ + $\frac{√x}{x-1}$ ):($\frac{√x}{√x-1}$ -1) vs x $\geq$ 0, x$\neq$ 1 a, tìm x nguyên để M = A.$\frac{√x+1}{2√x +1}$ + $\frac{x-√x - 5}{√x+3 }$ có giá trị nguyên
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