Đáp án:
$a) 1$
$b) 9$
Giải thích các bước giải:
$a) A=\dfrac{2020×125+1000}{126×2020-1020}$
$⇒A=\dfrac{2020×125+1000}{125×2020+2020-1020}$
$⇒A=\dfrac{2020×125+1000}{125×2020+1000}$
$⇒A=1$
$b) (\dfrac{1}{11×13}+\dfrac{1}{13×15}+...+\dfrac{1}{19×21})×462+x=19$
$⇒\dfrac{1}{2} (\dfrac{2}{11×13}+\dfrac{2}{13×15} +...+\dfrac{2}{19×21})×462+x=19$
$⇒(\dfrac{1}{11}- \dfrac{1}{13} +\dfrac{1}{13}+...+\dfrac{1}{19}-\dfrac{1}{21})×231+x=19$
$⇒( \dfrac{1}{11}- \dfrac{1}{21})×231+x=19$
$⇒10+x=19$
$⇒x=19-10$
$⇒x=9$