a) Giải phương trình \(\frac{{2{x^2}\left( {7 - x} \right)}}{{\sqrt {3 - x} }} = x\left( {x - 7} \right)\)
b) Giải hệ phương trình \(\left\{ \begin{array}{l}\left( {x + 3} \right)\left( {x - 1} \right) = \left( {y - 2} \right)\left( {x + 3} \right)\\\left( {x - 1} \right)\sqrt {{y^2} - 5y + 8} = {\left( {y - 2} \right)^2}\end{array} \right.\)
A.\(\begin{array}{l}a)\,\,S = \left\{ {0; - 1;\frac{3}{4}} \right\}\\b)\,\,\left( {x;y} \right) = \left( {1;2} \right);\,\,\left( {x;y} \right) = \left( {3;4} \right)\end{array}\)
B.\(\begin{array}{l}a)\,\,S = \left\{ {0; - 1} \right\}\\b)\,\,\left( {x;y} \right) = \left( {3;4} \right)\end{array}\)
C.\(\begin{array}{l}a)\,\,S = \left\{ {0; - 1} \right\}\\b)\,\,\left( {x;y} \right) = \left( {1;2} \right);\,\,\left( {x;y} \right) = \left( {3;4} \right)\end{array}\)
D.\(\begin{array}{l}a)\,\,S = \left\{ {0; - 1;\frac{3}{4};7} \right\}\\b)\,\,\left( {x;y} \right) = \left( {1;2} \right);\,\,\left( {x;y} \right) = \left( {3;4} \right)\end{array}\)
b) Giải hệ phương trình \(\left\{ \begin{array}{l}\left( {x + 3} \right)\left( {x - 1} \right) = \left( {y - 2} \right)\left( {x + 3} \right)\\\left( {x - 1} \right)\sqrt {{y^2} - 5y + 8} = {\left( {y - 2} \right)^2}\end{array} \right.\)
A.\(\begin{array}{l}a)\,\,S = \left\{ {0; - 1;\frac{3}{4}} \right\}\\b)\,\,\left( {x;y} \right) = \left( {1;2} \right);\,\,\left( {x;y} \right) = \left( {3;4} \right)\end{array}\)
B.\(\begin{array}{l}a)\,\,S = \left\{ {0; - 1} \right\}\\b)\,\,\left( {x;y} \right) = \left( {3;4} \right)\end{array}\)
C.\(\begin{array}{l}a)\,\,S = \left\{ {0; - 1} \right\}\\b)\,\,\left( {x;y} \right) = \left( {1;2} \right);\,\,\left( {x;y} \right) = \left( {3;4} \right)\end{array}\)
D.\(\begin{array}{l}a)\,\,S = \left\{ {0; - 1;\frac{3}{4};7} \right\}\\b)\,\,\left( {x;y} \right) = \left( {1;2} \right);\,\,\left( {x;y} \right) = \left( {3;4} \right)\end{array}\)
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Hóa Học lớp 12
