Đáp án:
\(\begin{array}{l}
a)\\
{C_M}NaOH = 1M\\
b)\\
{C_M}HCl = 0,15M\\
c)\\
{C_M}A{l_2}{(S{O_4})_3} = 0,0075(M)\\
d)\\
{C_M}NaOH = 0,15M
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
{n_{NaOH}} = \dfrac{4}{{40}} = 0,1\,mol\\
{V_{{\rm{dd}}NaOH}} = {V_{{H_2}O}} = 0,1\,l\\
{C_M}NaOH = \dfrac{{0,1}}{{0,1}} = 1M\\
b)\\
{n_{HCl}} = \dfrac{{3,36}}{{22,4}} = 0,15\,mol\\
{V_{{\rm{dd}}HCl}} = {V_{{H_2}O}} = 1l\\
{C_M}HCl = \dfrac{{0,15}}{1} = 0,15M\\
c)\\
{n_{A{l_2}{{(S{O_4})}_3}}} = \dfrac{{0,513}}{{342}} = 0,0015\,mol\\
{V_{{\rm{dd}}HCl}} = {V_{{H_2}O}} = 0,2l\\
{C_M}A{l_2}{(S{O_4})_3} = \dfrac{{0,0015}}{{0,2}} = 0,0075(M)\\
d)\\
{n_{NaOH}} = 0,1 \times 0,1 + 0,1 \times 0,2 = 0,03\,mol\\
{V_{{\rm{dd}}}} = 0,1 + 0,1 = 0,2\,mol\\
{C_M}NaOH = \dfrac{{0,03}}{{0,2}} = 0,15M
\end{array}\)
