Đáp án:
a)$\dfrac{1}{33}\\
b) \dfrac{-19}{18}>\dfrac{-13}{12}$
Giải thích các bước giải:
$a)\dfrac{16.18-16.17}{15.33+33}=\dfrac{16(18-17)}{33(15+1)}=\dfrac{16}{33.16}=\dfrac{1}{33}\\
b)\dfrac{-13}{12}=\dfrac{(-13).3}{12.3}=\dfrac{-39}{36}\\
\dfrac{-19}{18}=\dfrac{(-19).2}{36}=\dfrac{-38}{36}$
Do $-38>-39\Rightarrow \dfrac{-38}{36}>\dfrac{-39}{36}$
$\Rightarrow \dfrac{-19}{18}>\dfrac{-13}{12}$