Đáp án:
a.$\dfrac{-11}{5}<\dfrac{-7}4$
b.$\dfrac{2020}{-2021}>\dfrac{-2022}{2021}$
Giải thích các bước giải:
a.Ta có:
$-2=\dfrac{-2\cdot 5}{5}=\dfrac{-10}{5}>\dfrac{-11}{5}$
$-2=\dfrac{-2\cdot 4}{4}=\dfrac{-8}{4}<\dfrac{-7}4$
$\to \dfrac{-11}{5}<\dfrac{-7}4$
b.Ta có:
$\dfrac{2020}{-2021}=\dfrac{-2020}{2021}>\dfrac{-2022}{2021}$