Đáp án:
Giải thích các bước giải:
a)
$Al_4C_3 + 12H_2O \to 4Al(OH)_3 + 4CH_4$
$2CH_4 \xrightarrow{t^o,lln} C_2H_2 + 3H_2$
$C_2H_2 + H_2 \xrightarrow{t^o,xt} C_2H_4$
$C_2H_4 + 3H_2 \xrightarrow{t^o,xt} C_2H_{6}$
$C_2H_6 + Cl_2 \to C_2H_5Cl + HCl$
$C_2H_5Cl + KOH \to C_2H_5OH + KCl$
$C_2H_5OH + CuO \xrightarrow{t^o} Cu + CH_3CHO + H_2O$
$CH_3CHO + \dfrac{1}{2}O_2 \xrightarrow{t^o,xt} CH_3COOH$
$CH_3COOH + Na \to CH_3COONa + \dfrac{1}{2}H_2$
b)
$CaC_2 + 2H_2O \to Ca(OH)_2 + C_2H_2$
$C_2H_2 + H_2 \xrightarrow{t^o,xt} C_2H_4$
$C_2H_4 + HCl \to C_2H_5Cl $
$2C_2H_5Cl + 2Na \xrightarrow{ete\ khan} C_4H_{10} + 2NaCl$
$C_4H_{10} \xrightarrow{t^o,xt} C_2H_4 + C_2H_6$
$C_2H_4 + H_2O \xrightarrow{t^o,xt} C_2H_5OH$
$C_2H_5OH + CuO \xrightarrow{t^o} CH_3CHO + Cu + H_2O$
$CH_3CHO + \dfrac{1}{2}O_2 \xrightarrow{t^o,xt} CH_3COOH$
$CH_3COOH + NaOH \to CH_3COONa + H_2O$
$CH_3COONa + NaOH \xrightarrow{t^o,CaO} CH_4 + Na_2CO_3$
$CH_4 + Cl_2 \to CH_3Cl + HCl$
